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+--- Thread: regex to eliminate port number from url (/showthread.php?tid=68241)
regex to eliminate port number from url - cupboy1 - 06-14-2017
I tried this and some other things. What I need in this example would be to return just localhost without the colon and the port number. There may or may not be a port number and it needs to return a value in both cases. Currently it returns 'localhost:8080' in [1][0] but I want just 'localhost' to be in there.
Code:
$subject1 = "localhost:8080";
$subject2 = "localhost";
$pattern = "/(.*)\:{0,1}(.*)/";
$retval = preg_match($pattern, $subject1, $matches, PREG_OFFSET_CAPTURE);RE: regex to eliminate port number from url - rtenny - 06-15-2017
If you just want to remove the port number from the URL i would do this
$pattern = "/:[0-9]*/";
$url = preg_replace($pattern, '', $subject1);
even if $subject1 = localhost:8080/index.php it will correctly return localhost/index.php
RE: regex to eliminate port number from url - skunkbad - 06-15-2017
Technically, this is a valid URL:
http://username:[email protected]:8080/one/two/three?legal=:40#:yes
So you are better off parsing it with PHP's parse_url function:
PHP Code:
<?php
$url = 'http://username:[email protected]:8080/one/two/three?legal=:40#:yes';
$parsed_url = parse_url( $url );
echo '<pre>';
print_r( $parsed_url );
echo '</pre>';
function reassemble_without_port( $parsed_url )
{
$url = '';
if( isset( $parsed_url['scheme'] ) )
$url .= $parsed_url['scheme'] . '://';
if( isset( $parsed_url['user'], $parsed_url['pass'] ) )
$url .= $parsed_url['user'] . ':' . $parsed_url['pass'] . '@';
$url .= $parsed_url['host'];
if( isset( $parsed_url['path'] ) )
$url .= $parsed_url['path'];
if( isset( $parsed_url['query'] ) )
$url .= '?' . $parsed_url['query'];
if( isset( $parsed_url['fragment'] ) )
$url .= '#' . $parsed_url['fragment'];
return $url;
}
echo reassemble_without_port( $parsed_url );