VS Code typenit parent class (interface)

PHP Code:

class A {
}

class B extends A {
}

interface AI {
    public function test(A $a);
}

class Run implements AI {
    public function test(B $b) // Method 'App\Services\Run::test()' is not compatible with method 'App\Services\AI::test()'.intelephense(1038)
    {
        return;
    }
} 


Can you help with that? In fact, this is acceptable, since class B is extensible to A

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No, it is not acceptable. B is not A.
See https://3v4l.org/nHa6i

But the opposite is acceptable.
See https://3v4l.org/c1sQb

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PHP Code:

class A {
}

class B extends A {
}

interface AI {
    public function test(A $a);
}

class Run implements AI {
    /**
    * @param B $a
    */
    public function test(A $a)
    {
        return __METHOD__;
    }
}


$b = new B();
$run = (new Run())->test($b); 


Sorry, I didn't wake up. Yes, we can't change the interface definition. It is necessary to clarify in PHPDoc. I hurried

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