my radio button not working properly? |
Code: <input type="radio" name="kvr" checked="checked" onclick="hideall1();showit1('x1')" <?php if (isset($_POST['kvr']) && $_POST['kvr']=="yes") echo "checked";?> value="yes" >Same at first radio button click the form should not be submitted, after click second radio button the value only be passed. why? need suggestion
<input type="radio" name="kvr" checked="checked" onclick="hideall1();showit1('x1')" <?php if (isset($_POST['kvr']) && $_POST['kvr']=="yes") echo "checked";?> value="yes" >Same
<input type="radio" name="kvr" onclick="hideall();showit('x1')" <?php if (isset($_POST['kvr']) && $_POST['kvr']=="no") echo "checked";?> value="no" >Other ----------------------- remove checked="checked" from first line (11-15-2018, 05:00 AM)abGorad Wrote: <input type="radio" name="kvr" checked="checked" onclick="hideall1();showit1('x1')" <?php if (isset($_POST['kvr']) && $_POST['kvr']=="yes") echo "checked";?> value="yes" >Same default first radio button should be checked when loading form.
Reading this question, I wonder why you keep ignoring the numerous advices that I and others have given you about the CI fundamentals, form validation library, form helper and jQuery. Why asking questions in a CI forum if you intend to stick to traditional php and javascript anyway???
(11-15-2018, 04:16 AM)kvanaraj Wrote: after click second radio button the value only be passed. why?If you are asking "Why is it only the value of the second radiobutton gets passed?" If these are in a radiogroup. Only one radio button within the same radiogroup may be selected at a time. Only the value of the selected radio button will be sent to the server. If you want multiple values you should probably be using checkbox. |
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