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+--- Thread: form_dropdown and selected (/showthread.php?tid=17932)
form_dropdown and selected - El Forum - 04-20-2009
[eluser]nealumney[/eluser]
I have an array of items I want to include as a 'drop down' and so I have (within my view) the following code:
echo form_dropdown('manufacturer', $mftrs);
all is well and presents a list of manufacturers for the user to select from. However, I need the first item to be a 'Please select ... ' item, and have this as an entry in the $mftrs' array. What I want to do is to have this 'selected' rather than just appear in the list somewhere. I could of course manually do the following:
<select name="manufacturer">
<option value="">Please select ...</option>
<?php
foreach ($mftr $key as $row)
{ ?>
<option value="<?php echo $key ;?>" ><?php echo $row ; ?></option>
<?php } ?>
</select>
Is there anyway of using the form_dropdown method with an array to choose the selected item?
Thanks,
Neal
form_dropdown and selected - El Forum - 04-20-2009
[eluser]The Wizard[/eluser]
hello, there is a workarround i frequently use, just a sec.
form_dropdown and selected - El Forum - 04-20-2009
[eluser]The Wizard[/eluser]
Code:
function Dropdown_CreditCard( $name, $user_id, $selected_id = '', $reload = FALSE )
{
$this->load->database('c88v2');
$this->db->select('id, user_id, type, name, number, cvv2, date_month, date_year');
$this->db->from('premium_creditcard');
$this->db->where( 'user_id', $user_id ); // <--- C A U T I O N
$this->db->where( 'status', 'ACTIVE' );
$query = $this->db->get();
$num_rows = $query->num_rows();
$result_array = array();
if ( $num_rows <= 0)
{
$result_array['-1'] = ' --------- ';
}
else
{
$result_array['-1'] = ' - Select - ';
foreach ($query->result_array() as $row)
{
$result_array[ $row['id'] ] = $row['number'] .' - '. $row['type'] .' - '. $row['name'];
}
}
$javascript = $reload == TRUE ? 'onchange="this.form.submit();"' : '';
$this->load->helper('form');
return form_dropdown( $name, $result_array, $selected_id, $javascript );
}thats the code and
Code:
// in validation
..
$creditcard_id = $this->input->post('creditcard_id');
$data['creditcard_dropdown'] = $this->model_premium->Dropdown_CreditCard( 'creditcard_id', $user_id, $creditcard_id, TRUE );
..that would be the use of it.
i hope it helps
form_dropdown and selected - El Forum - 04-20-2009
[eluser]slowgary[/eluser]
This is another reason why I don't really get using helpers to generate markup. The markup is so simple to begin with, does it really simplify anything? What's the benefit?
If you MUST do it this way, a crappy hack could be to just use JavaScript to insert the first element...
Code:
< script type='text/javascript' >
$('select').prepend("<option selected='selected' disabled='disabled'>Please select...</option>");
< /script>This example uses jQuery
form_dropdown and selected - El Forum - 04-20-2009
[eluser]Asinox[/eluser]
Well my way:
Code:
function listCombox(){ //COMBOX
$query = $this->db->get('table');
if($query->num_rows()>0){
$data[] = 'Select ONE';
foreach($query->result_array() as $row){
$data[$row['id']] = $row['name'];
}
return $data;
}else{
return FALSE;
}
$query->free_result();
}