Uri Class problem - Printable Version

Uri Class problem - Printable Version

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+--- Thread: Uri Class problem (/showthread.php?tid=29590)

Uri Class problem - El Forum - 04-14-2010

[eluser]Ngulo[/eluser]
hi all i have a controller (downloads.php) with this function (templates) after the main index():

Code:
function templates()

        {

             $tab_from_uri=$this->uri->segment(3);

                switch($tab_form_uri)

                {

                    case "1":

                        $tab = "tab1";

                    break;

                    case "2":

                        $tab = "tab2";

                    break;

                    case "3":

                        $tab ="tab3";

                    break;

                }

               $data['asd']=$this->db->order_by("data_templx","asc")->get(''.$tab);

               $this->load->view('downloads_view',$data);

        }

my links are

Code:
anchor('downloads/templates','List')

so they took me rightly to /index.php/downloads/templates/3 ...as i want

but,when i click the link ,loading the view,i take this error:

Code:
Message: Undefined variable: tab_form_uri

i can't find any error,i've prooved also changing uri->segment(3) to uri->segment(4)......this is not the problem i guess Smile

any suggestions?

Uri Class problem - El Forum - 04-14-2010

[eluser]WanWizard[/eluser]
It probably also tells you where PHP has detected this undefined variable? Because that one isn't used in your code segment, you use $tab_from_uri, and not $tab_form_uri...

Uri Class problem - El Forum - 04-14-2010

[eluser]Ngulo[/eluser]
oh my god!!!!!!!!!!!!! sorry!!!!!!! ahahahah what i stupid i am!!!

really sorry Big Grin

,sometimes i would like to kill myself Big Grin

eheheh

sorry for another question

when i take

$data['data_from_uri']=$this->uri->segment();

and insert this into a db, is this prep from the helper or i need to escape it after:
$data['data_from_uri']=mysql_real_escape_string($this->uri->segment()); (for example)

??

really thanks man Wink

Uri Class problem - El Forum - 04-14-2010

[eluser]WanWizard[/eluser]
Depends on how you insert it. If you use Active Record everything will be escaped for you, unless you disable it.
The manual (have you read it? Wink

) is very clear about this.

Uri Class problem - El Forum - 04-15-2010

[eluser]Ngulo[/eluser]
yes man,i understand ,and i always use active records to running queries, but i don't mind what you mean with disable escape on active record class? how do you disable escapes in this?
i can't find any suggest on active records guide on this argument ... Sad

i guess i'm blind Tongue

and what about uri-segment()? is this automaticly escaped or not?

really thanks again Wink

Uri Class problem - El Forum - 04-15-2010

[eluser]WanWizard[/eluser]
As per the manual:

Quote:If you are using a database that CodeIgniter escapes queries for, you can prevent escaping content by passing an optional third argument, and setting it to FALSE.

uri->segment() is a retrieval function, there is nothing to escape.

Uri Class problem - El Forum - 04-15-2010

[eluser]Ngulo[/eluser]
pardon me Wan i'm new on PHP imn general and on CI's to Tongue

so if i don't specify any third parameter in active class the data are escaped automaticly?right?

thanks again Wink