Dynamic database selection - Printable Version +- CodeIgniter Forums (https://forum.codeigniter.com) +-- Forum: Archived Discussions (https://forum.codeigniter.com/forumdisplay.php?fid=20) +--- Forum: Archived Development & Programming (https://forum.codeigniter.com/forumdisplay.php?fid=23) +--- Thread: Dynamic database selection (/showthread.php?tid=36441) |
Dynamic database selection - El Forum - 12-01-2010 [eluser]cpass78[/eluser] Hello, I have a need to connect to many databases from a form to check if certain tables exist. There could potentially be hundreds of DB's and the names are not known yet. I'd need to connect to one based on Code: $this->input->post(); Is there any way to do this without messing with the database.php config file? My username password and host would all remain the same just the db would need to change. I did try Code: $config['database'] = "study_".$this->studycode; Thank you! Dynamic database selection - El Forum - 12-01-2010 [eluser]WanWizard[/eluser] You can load the database (this way) only once, after which it is assigned to $this->db. If you try to load another one, it detects it's already loaded, and returns false. Secondly, if you try to load a database with a manual config, you need to pass all information in the array. If you want to reuse the default config, you have to load that first. Try Code: // load the database config Dynamic database selection - El Forum - 12-01-2010 [eluser]cpass78[/eluser] Thanks for the response, That looks like it will work but i just kept it simple with Code: $select = @mysql_select_db("study_".$this->studycode); May or may not be a "proper way way to do it but it works for the time being. Thank you again! Dynamic database selection - El Forum - 12-01-2010 [eluser]cpass78[/eluser] Actually i chose to implement your method and it works like a charm, solved it for me. Thanks a million |