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+--- Thread: help on this anyone? (/showthread.php?tid=3866)
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help on this anyone? - El Forum - 10-26-2007
[eluser]mistress_shiira[/eluser]
Quote:<div style="font: 12px normal Verdana;color:red;">
<?php
if($this->validation->error_string){
echo $this->validation->error_string;
echo "enable_button();";
}
?>
</div>
hey guys can you help me with this?
i have a simple sign up form..when the user submits the form and there is still a validation error, i want the submit button to be enabled.the submit button was disabled on load fyi.
the code above doesnt seem to work...
help on this anyone? - El Forum - 10-26-2007
[eluser]xwero[/eluser]
Have you tried
Code:
if($this->validation->error_string != '')help on this anyone? - El Forum - 10-26-2007
[eluser]mistress_shiira[/eluser]
[quote author="xwero" date="1193407333"]Have you tried
Code:
if($this->validation->error_string != '')the code ive posted already checks for validation errors and echoes the validation error.
what i wanted is that when there is a validation error,the submit button should be enabled.
help on this anyone? - El Forum - 10-26-2007
[eluser]ballen[/eluser]
You could try something like
Code:
<div style="font: 12px normal Verdana;color:red;">
<?php
$disabled = "disabled";
if($this->validation->error_string){
echo $this->validation->error_string;
$disabled = "";
}
?>
</div>and on your button
Code:
disabled = <?php echo $disabled; ?>help on this anyone? - El Forum - 10-26-2007
[eluser]xwero[/eluser]
how do you disable it? I believe you used xajax but i'm not familiar with it.
I'm a jquery user and the way i do something like this is to change the class.
Code:
// view
<input type="submit" class="<?php echo $buttonclass; ?>" value="send">
// js
$(function(){
$('.enable:disabled').each(function(){
this.disabled = false;
});
$('.disable:enabled').each(function(){
this.disabled = true;
});
});I hope this can help you
help on this anyone? - El Forum - 10-26-2007
[eluser]mistress_shiira[/eluser]
Quote:<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">im already posting the view file for this...
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Sign up Form</title>
<link rel="stylesheet" type="text/css" href="../system/application/css/calc.css" media="screen" />
<?=form_open('Validate'); ?>
<?=$xajax_js?>
</head>
<body onload="sign_up();">
<!--
xajax.callback.global.onRequest=
function(){document.getElementById('loadingMessage').style.display='block';};
xajax.callback.global.onComplete = function(){
document.getElementById('loadingMessage').style.display='none';
};
function sign_up(){
xajax.$('submit').disabled=true;
}
function enable_button(){
xajax.$('submit').disabled = false;
}
// -->
<div style="font: 12px normal Verdana;color:red;">
<?php
if($this->validation->error_string){
echo $this->validation->error_string;
echo "enable_button();";
}
?>
</div>
<div style="font: 12px normal Comic Sans;color:#000;">
<p><label for="username">Username:</label><br />
<input type="text" id="username" name="username" tabindex="1" value="<?=$this->validation->username;?>" /></p>
<input type="button" name="available" id="available" value="Check availability" tabindex="2" onclick="xajax_name_check(xajax.$('username').value);"/><br />
<p id="hello"></p>
<p><label for="password">Password:</label><br />
<input type="password" id="password" name="password" value="<?=$this->validation->password;?>" tabindex="3" /></p>
<p><label for="email">Email Address:</label><br />
<input type="text" id="email" name="email" value="<?=$this->validation->email;?>" tabindex="4" /></p>
<p><label for="country">Country</label><br />
<input type="text" id="country" name="country" value="<?=$this->validation->country;?>" tabindex="5"/></p>
<input type="submit" id="submit" name="submit" value="Submit" />
<?=form_close();?>
</div>
<div id="loadingMessage">
Processing your request...
<img src="../system/application/views/loader.gif" alt="" />
</div>
<div id="outputDiv">
</div>
help on this anyone? - El Forum - 10-26-2007
[eluser]xwero[/eluser]
Seeing this code the function is not going to to be triggered because there is no trigger for it (oncomplete, onload).
You could try
Code:
echo "<script>enable_button();</script>";You should check the xajax documentation to see if you can attach the enable_button function to the oncomplete event that is how it works in jquery.
help on this anyone? - El Forum - 10-26-2007
[eluser]mistress_shiira[/eluser]
[quote author="xwero" date="1193417083"]Seeing this code the function is not going to to be triggered because there is no trigger for it (oncomplete, onload).
You could try
Code:
echo "<script>enable_button();</script>";You should check the xajax documentation to see if you can attach the enable_button function to the oncomplete event that is how it works in jquery.[/quote]
ive tried that though but it seems its not working..but thanks for the help.ill try to look it up on xajax implementation.thanks a lot xwero.
help on this anyone? - El Forum - 10-26-2007
[eluser]xwero[/eluser]
I don't know if you would consider this but instead of enable/disable the button why don't you hide/show the button? This can be done using only php.
help on this anyone? - El Forum - 10-26-2007
[eluser]Pygon[/eluser]
should work with:
Code:
echo "<script type=\"text/javascript\">enable_button()</script>"