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MySQL DATE_FORMAT with Active Record - Printable Version +- CodeIgniter Forums (https://forum.codeigniter.com) +-- Forum: Archived Discussions (https://forum.codeigniter.com/forumdisplay.php?fid=20) +--- Forum: Archived Development & Programming (https://forum.codeigniter.com/forumdisplay.php?fid=23) +--- Thread: MySQL DATE_FORMAT with Active Record (/showthread.php?tid=6863) |
MySQL DATE_FORMAT with Active Record - El Forum - 03-14-2008 [eluser]Référencement Google[/eluser] Hi, How would you do this query using Active Record ? Code: SELECT DATE_FORMAT(your_date_field, 'Year: %Y Month: %m Day: %d') AS formated_date FROM your_table; MySQL DATE_FORMAT with Active Record - El Forum - 03-14-2008 [eluser]mironcho[/eluser] Hi, You can try this: Code: $this->db->select("DATE_FORMAT(your_date_field, 'Year: %Y Month: %m Day: %d') AS formated_date"); MySQL DATE_FORMAT with Active Record - El Forum - 03-14-2008 [eluser]Référencement Google[/eluser] Whoooops... just got it ! If it can help somebody: Code: function list_all($lang, $limit = FALSE, $offset = FALSE) MySQL DATE_FORMAT with Active Record - El Forum - 02-20-2009 [eluser]The Wizard[/eluser] just add a FALSE @ select. like: Code: $this->db->select("DATE_FORMAT(your_date_field, 'Year: %Y Month: %m Day: %d') AS formated_date", FALSE ); // <-- F A L S E |