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+--- Thread: Solved: non-object error (/showthread.php?tid=70563)
Solved: non-object error - davy_yg - 04-26-2018
Hello,
I am trying to view the file image after uploading and I am getting non-object error. How to call the file name?
upload_success.php
Code:
[code]
<html>
<head>
<title>Upload Form</title>
</head>
<body>
<h3>Your file was successfully uploaded!</h3>
<ul>
<?php foreach ($upload_data as $item => $value):?><?php endforeach; ?>
</ul>
<img src="uploads/".$upload_data->file_name>
<p><?php echo anchor('upload', 'Upload Another File!'); ?></p>
</body>
</html>[/code]
RE: non-object error - InsiteFX - 04-27-2018
Because it is an Associated array and your trying to access it as an object.
Do you even know the difference between an associated array or an object etc;?
RE: non-object error - davy_yg - 04-28-2018
associated array something like:
https://www.w3schools.com/php/php_arrays.asp ?
How to fix the code?
RE: non-object error - davy_yg - 04-28-2018
I already able to capture the file name but unable to print it out correctly.
controllers/upload_image.php
$data = array('upload_data' => $this->upload->data(),
'file_name' => $this->upload->data('file_name')
);
$this->photo_model->insert_pic();
$this->load->view('upload_success', $data);
views/upload_success.php
<img scr="uploads/"<?php echo $file_name; ?>>
If I checked through inspect element I get this html code:
<img src="uploads/"davy210.png="">
which is in correct.
RE: non-object error - davy_yg - 04-28-2018
I finally find the answer to this one! Thanks.
<img src="<?php echo base_url('/uploads/'.$file_name); ?>">