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+--- Thread: call an ajax request to one Controller... what the solution since out of web access (/showthread.php?tid=71290)
call an ajax request to one Controller... what the solution since out of web access - lsepolis123 - 07-28-2018
I have my Controllers Views and Models and all application folder out of web root[public_html] Not accessible
I want call an ajax request to one Controller... what the solution since out of access?
Cent OS 6.7 LAMP
if create for the Controller file a soft link "ln -s /x/y/appplication/controllers/Xcontroller.php /x/y/public_html/assets/php/link-to-controller.php"
should work calling soft link in web root...? or same thing is? any other solution?
RE: call an ajax request to one Controller... what the solution since out of web access - InsiteFX - 07-28-2018
As long as you use the full url path to the controller/method it
should not matter.
I have mine outside and I can access them.
RE: call an ajax request to one Controller... what the solution since out of web access - plonknimbuzz - 07-28-2018
try chown them
RE: call an ajax request to one Controller... what the solution since out of web access - lsepolis123 - 07-28-2018
(07-28-2018, 09:03 AM)InsiteFX Wrote: As long as you use the full url path to the controller/method it
should not matter.
I have mine outside and I can access them.
YOU MEAN access Controller from Ajax/jQuery/HTML5... ?
Can you provide your URL as example used by your jQuery/Ajax??
RE: call an ajax request to one Controller... what the solution since out of web access - lsepolis123 - 07-28-2018
(07-28-2018, 01:56 PM)plonknimbuzz Wrote: try chown them
what you mean ? >>>
try chown them
change owner(user):group with this command to what?
can you provide your ajax url as example... or at least a sample ajax url similar to yours?
RE: call an ajax request to one Controller... what the solution since out of web access - InsiteFX - 07-29-2018
Code:
<head>
<!-- setup base_url() and site_url() for JavaScript -->
<script>
var baseUrl = "<?php echo base_url(); ?>";
var siteUrl = "<?php echo site_url(); ?>";
</script>
</head>
jQuery CODE:
$.ajax({
url: baseUrl + "controller/method",
// other parameters
});