How to use the pagination with view parser? - Printable Version +- CodeIgniter Forums (https://forum.codeigniter.com) +-- Forum: CodeIgniter 4 (https://forum.codeigniter.com/forumdisplay.php?fid=28) +--- Forum: CodeIgniter 4 Support (https://forum.codeigniter.com/forumdisplay.php?fid=30) +--- Thread: How to use the pagination with view parser? (/showthread.php?tid=74713) |
How to use the pagination with view parser? - luispastendev - 10-28-2019 Hello there! I am building a view with pagination with view parser, the problem is how I spend the value of pager to build my links? since it is an object and in view parser it is not possible to use them Code: $data = [ RE: How to use the pagination with view parser? - ciadmin - 10-28-2019 At the bottom of the UG page (https://codeigniter4.github.io/userguide/libraries/pagination.html), a pagination objet will have `links()` that you can inject into your view at the proper place. I thought there was something inside the Model class as well, but it isn't jumping out at me. RE: How to use the pagination with view parser? - deepakkushwaha - 10-29-2019 Not having idea how to do it... If you find the solution please tell me too. RE: How to use the pagination with view parser? - eternity6 - 07-02-2021 Well...You can simple put HTML result of pager inside an array with a specific label in your control and then parser it with a { code } in the template. For example Controller: PHP Code: $this->data['page_pagination'] = $data['pager']->links(); In your template view use code with ! for don't print HTML code Code: <div class="pagination">{! page_pagination !}</div> |