Load Dynamic Model - Printable Version

Load Dynamic Model - Printable Version

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+--- Thread: Load Dynamic Model (/showthread.php?tid=75508)

Load Dynamic Model - lahoussaine - 02-13-2020

Hello

I would like use a dynamic model, i want use loop to load multiple model dynamically, in CI3 work fine and in CI4 doesn't  work
this is an example

$array = array("Roles");
foreach ($array  as $key => $value) {

$UsersModel = new RolesModel(); // this work fine
$module = $key.'Model';
$module = new $module(); // this return error : Class 'RolesModel' not found

}

can you help me !

RE: Load Dynamic Model - falko - 02-13-2020

Add the "use" statement above your class.

I.e.

use App\Models\RolesModel;

class x extends Controller {

}

RE: Load Dynamic Model - lahoussaine - 02-13-2020

(02-13-2020, 01:49 PM)falko Wrote: Add the "use" statement above your class.

I.e.

use App\Models\RolesModel;

class x extends Controller {

}

This is top of my Controller :

Code:
namespace App\Controllers;

use CodeIgniter\Controller;

use App\Models\UsersModel;

use App\Models\RolesModel;

use App\Models\PermissionsModel;

class BaseController extends Controller

{

so when i use this syntax

Code:
$UsersModel = new RolesModel();

work fine without any problems !!!
wheen

Code:
$variable = "NameOfModel";

$UsersModel = new $variable();

not work

any idea !!

RE: Load Dynamic Model - lahoussaine - 02-13-2020

finally i found a solution for this problem
we have to must declare the full namespace path of a class

Code:
namespace App\Models

use App\Models\MyModel

...

case 1 :

$mymodule = new MyModel(); // work fine

case 2 :

$module = "MyModel";

$mymodule = new $module();  // Error not found 

case 3:

$module = "App\\Models\\MyModel";

$mymodule = new $module();              // work fine

for help

thx

RE: Load Dynamic Model - swapnil0804 - 09-18-2022

(02-13-2020, 04:43 PM)lahoussaine Wrote: finally i found a solution for this problem
we have to must declare the full namespace path of a class

Code:
namespace App\Models use App\Models\MyModel ... case 1 : $mymodule = new MyModel(); // work fine case 2 : $module = "MyModel"; $mymodule = new $module(); // Error not found case 3: $module = "App\\Models\\MyModel"; $mymodule = new $module(); // work fine

for help

thx

if you are in controller then you need something like this
$m="\App\Models".'\\'.$j['model'];
$model=new $m();