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+--- Thread: usint form_dropdown() (/showthread.php?tid=77450)
usint form_dropdown() - Martin_Salas - 09-02-2020
Hello, the table "types" is formed in the following way:
id | name | description
1 | one | none
2 | two | none
3 | three | NULL
this table is used to fill options in a <select> tag to do this I can use:
Code:
echo form_dropdown ('Types',$options);However $options is an associative array and I can't do the following in a controller:
Code:
// in a controller
$types = new Types ();
$options = $types->findAll();
// in a view
echo form_dropdown ('Types', $options);what I think I need is a method similar to findAll () but that returns an associative array to avoid what I currently do which is:
Code:
// in a controller
$ types = new Types ();
$ options = [];
foreach ($types->findAll() as $type) {
$ options = $options + [$type['id'] => $type['name']];
}
// in a view
echo form_dropdown ('Types', $options);My question is:
Is there a simple way to populate the $options array avoiding doing what I do?
Thank you very much for reading me and your help
RE: usint form_dropdown() - InsiteFX - 09-03-2020
Return an object from your model and then pass the object to this helper method.
PHP Code:
// -----------------------------------------------------------------------
/**
* Convert an Object to an Associated Array.
*
* Add to one of your helpers.
*/
if ( ! function_exists('objToAssocArray'))
{
function objToAssocArray(object $object)
{
// Converting object to associative array
return json_decode(json_encode($object), true);
}
}
Call it like this.
PHP Code:
$options = objToAssocArray($yourObject);
See if that works for you.
RE: usint form_dropdown() - Martin_Salas - 09-03-2020
Thank you very much for your answer, but the function you propose does not result in an associative array of the required form.
PHP Code:
$options = ['1' => 'asasasa',
'2' => 'some text',
'3' => 'some'
];
RE: usint form_dropdown() - InsiteFX - 09-04-2020
If it did not work then your not getting the data from the database as an object.
Another way of doing it is to type cast the type:
PHP Code:
$newTypes = (array)$types;
These will only work if you pass it an object array.