Conditional style for specific data in PHP

Conditional style for specific data in PHP - Printable Version

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+--- Thread: Conditional style for specific data in PHP (/showthread.php?tid=80370)

Conditional style for specific data in PHP - JJM50 - 10-24-2021

Currently I have a table displaying all of the agents and a count of their leads status shown in the same row. Now these agents can be Active or Inactive, but both are shown in my table. This active/inactive status is shown in my users table under the status column as either Y or N. Now this is the code I'm using to get my data:

Model Class:

Code:
function get_agentsreport(){        

$this->db->select("l.lead_status,cu.display_name,cu.status,count(*) as leadnum,l.enquiry_date");        

$this->db->from($this->table_name." as l");          

$this->db->join("crm_clients_users cu","cu.id= l.lead_agent","left");          $this->db->join("crm_clients_users cu2","cu2.id= l.external_agent","left");          $this->db->group_by("l.lead_status,cu.id,cu2.id");        

$query = $this->db->get();      }

View Class:

Code:
<?php

    $ls_arr = array(1=>'Open',8=>'Hot',2=>'Closed',3=>'Transacted',4=>'Dead',9=>'Follow Up',11=>'Working'); 

    foreach($groupedleads as $grplead){

        $statuses[] = $status = $ls_arr[$grplead["lead_status"]];

        if($grplead["display_name"] == NULL || $grplead["display_name"] == '')

            $grplead["display_name"] = "Unknown";

        if(isset($grplead["display_name"]))

            $display_names[] = $display_name = $grplead["display_name"];

        $leaddata[$status][$display_name] = $grplead["leadnum"];

        if($grplead['status'] == "N"){

                    $inactive_status == true;

                }

    }

    if(count($display_names) > 0)

      $display_names = array_unique($display_names);

?>

<table>

          <?php

          if(is_array($display_names))

            foreach($display_names as $display_name){ 

          ?>

              <tr>

                  <?php 

                    $total = 0;

                    $nonContact_total=0;

                    if ($inactive_status )

                      echo "<td style='background-color:#000'>".$display_name."</td>";

                    else

                      echo "<td>".$display_name."</td>";

                    foreach ($statuses as $status) {

                    ...

                    }

          <?php } ?>

</table>

Now I'm trying to differentiate the active and inactive users by a change in the style and as shown here I've tried if($grplead['status'] == "N"){$inactive_status == true;} but in my table it always goes to the else statement and doesn't compute the first if statement. I've also tried if($grplead['status'] == "Y"){$inactive_status == true;} but it gives the same output.

I've tried logging this status by print_r($grplead['status']); which gave the correct result like YYYYNY. So it is giving the correct status for each person, but for some reason it does not work in my if condition

RE: Conditional style for specific data in PHP - includebeer - 10-25-2021

The bug is here :

PHP Code:
if($grplead['status'] == "N"){
    $inactive_status == true;
} 

$inactive_status is never initialized. There should only be one equal sign, and it should be set to false if status is not equal to N :

PHP Code:
if($grplead['status'] == "N") {
    $inactive_status = true;
} else {
    $inactive_status = false;
} 

…and could be simplified like this :

PHP Code:
$inactive_status = ($grplead['status'] == "N"); 