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+--- Thread: Display a partial view based on the current view name (/showthread.php?tid=82185)
Display a partial view based on the current view name - b126 - 06-22-2022
Dear all,
I would like to display a header and menu on every view on my app BUT the logout.
I am using layouts already.
Let's take a quick example from the internet :
PHP Code:
<html>
<body>
<?=$this->include("partials/header")?>
<?=$this->renderSection("content")?>
<?=$this->include("partials/footer")?>
<body>
</html>
How to know which view is running when I am in the template php file.
Thank you!
RE: Display a partial view based on the current view name - kenjis - 06-22-2022
See https://codeigniter4.github.io/CodeIgniter4/outgoing/views.html#adding-dynamic-data-to-the-view
RE: Display a partial view based on the current view name - b126 - 06-24-2022
(06-22-2022, 04:16 PM)kenjis Wrote: See https://codeigniter4.github.io/CodeIgniter4/outgoing/views.html#adding-dynamic-data-to-the-view
I see no direct relation to the question. I don't want to add dynamic data to my views, I (fortunately) know how to do this
I am asking, how, in the view itself and based on its name (not in the controller), I can build a different display (insert or not a header).
Then, is there a way to know the name of the view running in the view itself?
Thank you
RE: Display a partial view based on the current view name - kenjis - 06-24-2022
(06-24-2022, 12:04 AM)b126 Wrote: Then, is there a way to know the name of the view running in the view itself?
No.
RE: Display a partial view based on the current view name - ikesela - 06-24-2022
pass parameter (view name) to view