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davy_yg · 04-26-2018, 10:16 PM

Hello,

I am trying to view the file image after uploading and I am getting non-object error. How to call the file name?

upload_success.php

Code:
[code]

<html>

<head>

<title>Upload Form</title>

</head>

<body>

<h3>Your file was successfully uploaded!</h3>

<ul>

<?php foreach ($upload_data as $item => $value):?>

<li><?php echo $item;?>: <?php echo $value;?></li>
<?php endforeach; ?>
</ul>

<img src="uploads/".$upload_data->file_name>

<p><?php echo anchor('upload', 'Upload Another File!'); ?></p>

</body>
</html>[/code]

" If I looks more intelligence please increase my reputation."

**InsiteFX** · 04-27-2018, 04:39 AM

Because it is an Associated array and your trying to access it as an object.

Do you even know the difference between an associated array or an object etc;?

What did you Try? What did you Get? What did you Expect?

Joined CodeIgniter Community 2009. ( Skype: insitfx )

davy_yg · 04-28-2018, 06:01 AM

associated array something like:

https://www.w3schools.com/php/php_arrays.asp ?

How to fix the code?

" If I looks more intelligence please increase my reputation."

davy_yg · 04-28-2018, 07:17 AM

I already able to capture the file name but unable to print it out correctly.

controllers/upload_image.php

$data = array('upload_data' => $this->upload->data(),
'file_name' => $this->upload->data('file_name')
);

$this->photo_model->insert_pic();

$this->load->view('upload_success', $data);

views/upload_success.php

<img scr="uploads/"<?php echo $file_name; ?>>

If I checked through inspect element I get this html code:

<img src="uploads/"davy210.png="">

which is in correct.

" If I looks more intelligence please increase my reputation."

davy_yg · 04-28-2018, 07:41 AM

I finally find the answer to this one! Thanks.

<img src="<?php echo base_url('/uploads/'.$file_name); ?>">

" If I looks more intelligence please increase my reputation."