language file inside a folder

Hey people!

I can use:

PHP Code:

lang('Errors.errorEmailMissing'); 


But, image that Errors.php is inside "app/Language/en/mysite/Errors.php". Now, how can I call the language?

PHP Code:

lang('mysite.Errors.errorEmailMissing'); //doesn't work, for example
lang('mysite/Errors.errorEmailMissing'); //too 


I need this because I want to use the same viewers files paths.

I don’t think that’s possible. Why do you want a “mysite” subdirectory? You are in app/Language, this is already your site’s language folder.

CodeIgniter 4 tutorials (EN/FR) - https://includebeer.com
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Thanks for help.

My site was an exemple. Can be admin or user folder too.

I already solved the problem seeing How CI do the things inside lang().

Thanks.

Thanks for help.

My site was an exemple. Can be admin or user folder too.

I already solved the problem seeing How CI do the things inside lang().

Thanks.

That’s cool. Care to share your solution?

CodeIgniter 4 tutorials (EN/FR) - https://includebeer.com
/*** NO support in private message - Use the forum! ***/

PHP Code:

//in ShowPage class
$dadosView['lang'] = getpagelang($template, $_SESSION['lang']); 


PHP Code:

<?php

namespace App\Helpers;

    /**
     * obtém todas as traduções de uma linguagem
     * @access public
     * @param String $page arquivo com o mesmo nome do Controller
     * @param String $lang linguagem em questão
     * @return Array
     */
    function getpagelang($page, $lang): Array
    {       
        //caminho do arquivo a ser lido
        $file = LANGUAGE_PATH.$lang.DIRECTORY_SEPARATOR. $page . '.php';

        //se o arquivo existir, retorna o conteúdo
        if (file_exists($file)) {

            //obtém os dados do arquivo de linguagem
            $arrLang = include $file;

            //verifica se é um array para retornar
            if(is_array($arrLang)) return $arrLang;
            else return array();

        } else echo lang('Errors.LangFile', [], $lang);

        //se o arquivo não existir, retorna um array vazio
        return array();
    } 


them, in controller:

PHP Code:

<?php

namespace App\Controllers;

use App\Libraries\ShowPage;

class Contato extends BaseController
{
    /**
     * Mostra a página inicial para este método
     */
    public function index(): void
    {
        //chama o conteúdo da página
        $template = 'site' . DIRECTORY_SEPARATOR . 'Contato';
        $menuWhere = 'contato';
        new ShowPage($template, $menuWhere);
    }
}