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Array member in function name OR How can a variable change its value depending on how I use it after it's declared?
#1

[eluser]TomTom[/eluser]
Hello everyone,

Apologies for a long post.

I have a multidimensional array which, in order to display its values in a view, should go through two foreach loops, like so:
Code:
<?php foreach ($content['id'] as $key1 => $taxon): ?>
<?php foreach ($taxon as $key2 => $instance): ?>

  <pre>&lt;?php print_r($instance); ?&gt;</pre>

  &lt;?php $name = $instance['taxon_field']; ?&gt;
  &lt;?php echo 'Value of the $name variable is: ' . $name; ?&gt;

&lt;?php endforeach; ?&gt;
&lt;?php endforeach; ?&gt;
The above code outputs the following result:
Code:
Array
(
    [unit_id] => 1
    [unit_author] => 0
    [unit_date] =>
    [unit_parent_id] => 0
    [unit_status] =>
    [unit_type_id] => 1
    [unit] => page_about
    [content_id] => 1
    [content_author] => 0
    [content_date] =>
    [content_parent_id] => 0
    [content_status] =>
    [content_taxon_id] => 1
    [content_unit_id] => 1
    [content] => Абаут
    [taxon_id] => 1
    [taxon_author] => 0
    [taxon_date] =>
    [taxon_field] => form_input
    [taxon_is_multiple] => 0
    [taxon_parent_id] => 0
    [taxon_status] =>
    [taxon_type_id] => 1
    [taxon] => page_title
    [type_id] => 1
    [type_author] => 0
    [type_date] =>
    [type_parent_id] => 0
    [type_status] =>
    [type] => page
)

Value of the $name variable is: form_input
. Now, I actually need to convert that variable value into a function name. I know that should be done with
Code:
&lt;?php $name(); ?&gt;
(I also know there are other ways, but either one should work equally good and either one returns the same error atm). Now, if I try to do this:
Code:
&lt;?php foreach ($content['id'] as $key1 => $taxon): ?&gt;
&lt;?php foreach ($taxon as $key2 => $instance): ?&gt;

  <pre>&lt;?php print_r($instance); ?&gt;</pre>

  &lt;?php $name = $instance['taxon_field']; ?&gt;
  &lt;?php echo $name(); ?&gt;

&lt;?php endforeach; ?&gt;
&lt;?php endforeach; ?&gt;
(note that the only difference are the parentheses in the variable name, which should turn it into a function), I get the following:
Code:
page

A PHP Error was encountered
Severity: Warning
Message:  Illegal string offset 'taxon_field'
Filename: views/edit.php
Line Number: 14

Fatal error: Call to undefined function p() in /views/edit.php on line 15
As it is obvious, when I added the () parentheses to the $name variable, for some reason the $instance array turned into a string with the value of the last array member $instance['type'] => page.

I tried to create another single-dimensioned array, with keys and values identical to those of $instance, and this time there were no errors. Can it be that the loops are creating some kind of conflict?

Any assistance is much appreciated.


Messages In This Thread
Array member in function name OR How can a variable change its value depending on how I use it after it's declared? - by El Forum - 09-14-2012, 06:02 AM



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