User Login

[eluser]BrianDHall[/eluser]
First, your $loggedIn will not be effected by your function because it returns a value that is simply discarded. Passing data though an array into a view happens when you call load->view() - you can't do it even by reference inside the view itself.

You'll need to have your checkLogin() function return true or false, and then do as Clip states above.

The next thing is you need to remove the if statements entirely and just see if your form displays sans login check. If it does, then you need to check the value of $loggedIn. If it is true then your form should display - if it doesn't then that's a clue what's the next thing that is wrong.