how to use set_select on a form to show the old value?

I will try that, in the meantime, here's what I did for testing:

PHP Code:

    $myValue = $booking->status;
    $testSetSelect = set_select('status', $booking->status);
    $testSetValue = set_value('status', $booking->status);
    $testSetCheckbox = set_checkbox('status', $booking->status);
    $testSetRadio = set_radio('status', $booking->status);
    $showResults = [$myValue,$testSetSelect,$testSetValue,$testSetCheckbox,$testSetRadio];

    dd($showResults); 


 
The result is quite strange:

Code:

$showResults array (5)
⇄0 => string (7) "request"
⇄1 => string (0) ""
⇄2 => string (7) "request"
⇄3 => string (0) ""
⇄4 => string (0) ""

---

HTML after output:

Code:

<form action="http://ci-demo/" method="post" accept-charset="utf-8">
                <select name="myselect">
                    <option value="one">One</option>
                    <option value="two" selected="selected">Two</option>
                    <option value="three">Three</option>
                </select>
                <button type="submit">Send</button>
</form>

No, html output has not changed, the default value one is still the one selected.

Check value dump($booking->status);

It is not empty, it contains the value that should be reassigned to the option (see my test... actually where it looks like only the set_checkbox function works :S).