Validating Numeric Data with in_array()

[eluser]Louis C.[/eluser]
I'd like to use in_array to determine to confirm that some data is numerical before I do things with it. But in_array() is confusing me with its output:

Code:

➜  ~  php -r 'print in_array(9, range(0, 10));'  
1%
➜  ~  php -r 'print in_array(-1, range(0, 10));'
➜  ~  php -r 'print in_array(m, range(0, 10));'
PHP Notice:  Use of undefined constant m - assumed 'm' in Command line code on line 1
1%
➜  ~  php -r 'print in_array('m', range(0, 10));'
PHP Notice:  Use of undefined constant m - assumed 'm' in Command line code on line 1
1%

Why does in_array say that both m and 'm' are contained in my numeric range?

What is the best way to determine if $number is between 1 and 10 in PHP?

Thanks,
Lou

[eluser]InsiteFX[/eluser]
Maybe define and set m to a value! It sholud not be enclosed in qoutes also!

[eluser]Louis C.[/eluser]
[quote author="InsiteFX" date="1303414379"]Maybe define and set m to a value! It sholud not be enclosed in qoutes also![/quote]

Thanks for the suggestion and advice. I'm relatively new to PHP.

I think I'll just need to verify the type of the variable with is_numeric() before using in_array() to search the array for it.

[eluser]danmontgomery[/eluser]
[quote author="Louis C." date="1303372607"]I'd like to use in_array to determine to confirm that some data is numerical before I do things with it. But in_array() is confusing me with its output:

Code:

➜  ~  php -r 'print in_array(9, range(0, 10));'  
1%
➜  ~  php -r 'print in_array(-1, range(0, 10));'
➜  ~  php -r 'print in_array(m, range(0, 10));'
PHP Notice:  Use of undefined constant m - assumed 'm' in Command line code on line 1
1%
➜  ~  php -r 'print in_array('m', range(0, 10));'
PHP Notice:  Use of undefined constant m - assumed 'm' in Command line code on line 1
1%

Why does in_array say that both m and 'm' are contained in my numeric range?

What is the best way to determine if $number is between 1 and 10 in PHP?

Thanks,
Lou[/quote]

Because your syntax is wrong.

You're doing:

Code:

print in_array(m, range(0, 10));

in both lines. As the error says, the undefined constant "m" is interpreted as a string. The integer value of "m" is 0, which is contained in the array.

http://php.net/manual/en/function.in-array.php

If the third parameter strict is set to TRUE then the in_array() function will also check the types of the needle in the haystack.

[eluser]Louis C.[/eluser]
noctrum, that is exactly what I was looking for. I just didn't read the docs hard enough. Thanks so much!