[eluser]alvaroeesti[/eluser]
UPDATE: Solved
I got the path to the pic by using the echo base url () function
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Hello,
I m trying to write this in OOP fashion, so it should print me the thumb
Code:
echo '<td><a href="closeup.php?id='.urlencode($row['id']).'"><img src="'.htmlspecialchars($row['thumb']).'"></a></td>';
This below is what I have to modify. I have tried variants but none has worked
Code:
<td><?php echo $encontrados->thumb?></td>
UPDATE.
Well I have managed the second part. It is like this:
Code:
<td><?php echo "<img src='$encontrados->thumb'>"?>
but while now it does show the typical icon of empty picture box, it does not find the picture. I am confused as to what is the path from the table cell in the database, just showing the name of the pic "picture.jpg" and the real call to it
Code:
<td><?php echo "<img src='$encontrados->thumb'>"?>
I dont know what else I have to write as path in here above. In fact I have placed the picture in all directories possible, xammp, htdocs, the folder of my application, and of course, the folder where the uploading takes place: assets/uploads/files.
The question:
when you have this "picture.jpg" written in your table cell of the database, where is that actually? where is the directory that gets called by just that ? I am referring to my laptop, not the webserver
thank you
A