how to use if condition in array variables?

How to use if condition in array

Code:

$insert = array();
       $insert[] = array(
           'appno' => $appno,
           'regno' => $regno,
          'certid' => $certid,
             'amt' => if($certid=1,8500 else 300 ,
             'date' => $today
               );      

PHP Code:

'amt' => $certid==1 ? 8500 : 300 , 


How to use if condition in array

Code:

$insert = array();
       $insert[] = array(
        'appno' => $appno,
        'regno' => $regno,
          'certid' => $certid,
             'amt' => if($certid=1,8500 else 300 ,
             'date' => $today
               );      

The key point that @Wouter60 makes (but does not explain) is that you assign a value of 1 to $certid, e.g. $certid=1. But what you really wanted to do was test for equality, e.g. $certid==1. What you should have written was

PHP Code:

 'amt' => if($certid==1,8500 else 300 , 


Wouter60 writes it more concisely by using a ternary statement instead of an "if/else" statement

PHP Code:

 'amt' => $certid==1 ? 8500 : 300 , 


The key point that @Wouter60 makes (but does not explain) is that you assign a value of 1 to $certid

Actually that wasn't my key point.
The syntax

PHP Code:

'amt' => if($certid=1,8500 else 300 , 


is wrong in every aspect (only one bracket, a comma at the wrong place, a single equal sign, etc.). It would certainly fail to get one value or another, based on a condition.

The syntax I suggested is:

<condition> ? <value1> : <value2>

This is a very userful one-line operation, in human language: if <condition> is true, then return value1, else return value 2.

The syntax

PHP Code:

'amt' => if($certid=1,8500 else 300 , 


is wrong in every aspect (only one bracket, a comma at the wrong place, a single equal sign, etc.). It would certainly fail to get one value or another, based on a condition.

Yeah. Well. There is that.
Forgive me for trying to add an explanation to your terse (and entirely correct) reply.