[eluser]Unknown[/eluser]
I have a problem with one query.
I have this code:
Code:
$this->db->select("f.*, (SELECT GROUP_CONCAT (CONCAT(p.nome, ' ', p.cognome) SEPARATOR ', ')
FROM professionisti p
WHERE p.id IN (SELECT r.id_professionista FROM registi r WHERE r.id_film = f.id)
) AS regista", FALSE);
$this->db->from($this->tables['film'] . ' f');
$this->db->where("f.pagina_html = '" . $film . "'");
$sql = $this->db->get();
return $sql->row();
but the above code return me the following error:
Quote:An Error Was Encountered
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SEPARATOR ', ') FROM professionisti p ' at line 1
SELECT f.*, (SELECT GROUP_CONCAT (CONCAT(p.nome, ' ', p.cognome) SEPARATOR ', ') FROM professionisti p WHERE p.id IN (SELECT r.id_professionista FROM registi r WHERE r.id_film = f.id) ) AS regista FROM (`film` f) WHERE f.pagina_html = 'grindhouse_us_version'
the query reported in the error message don't have problem in phpmyadmin.
I also tried with the following code:
Code:
$sql = "SELECT f.*, (SELECT GROUP_CONCAT (CONCAT(p.nome, ' ', p.cognome) SEPARATOR ', ')
FROM professionisti p
WHERE p.id IN (SELECT r.id_professionista FROM registi r WHERE r.id_film = f.id)
) AS regista
FROM film f
WHERE f.pagina_html = '" . $film . "'";
$query = $this->db->query($sql);
but return me the same error.
Where is the problem?
PS: excuse me for my english. I hope you can understand what i wrote.