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[SOLVED] - Honeypot - How to capture an exception

#1
Hi,

I am following the userguide instructions to use the honeypot class and almost everithing worked well.
But, I don't know how to capture a HoneyPotException when it is triggered when a bot fills the hidden field in the form.
I would like to capture that exception before it will be showed to user but I can't do that.
Even if I try to use a try/catch block, like so:

PHP Code:
try {
 
print_r($this->request->getPost());
}
catch (
Honeypotexception $e) {
echo 
$e->getMessage();


the print_r portion of my code is never reached.

So. How can I capture that exception to treat it before it is showed to user.


thank.
Ps. My english is a working in progress.
Reply

#2
Hi everyone

To make it work I decided to create my own filter, and put it inside app/filters.
The content is about the same that exists in system/filters/honeypot.
So, after do that, I went to app/Filter and I set the configuration to call my own HoneyPot filter instead of the native one.
Then, I could do anything I want there, including throw an Honeypotexception or not.

I hope I it helped someone.

Thankyou

(01-28-2020, 05:39 AM)reszko Wrote: Hi,

I am following the userguide instructions to use the honeypot class and almost everithing worked well.
But, I don't know how to capture a HoneyPotException when it is triggered when a bot fills the hidden field in the form.
I would like to capture that exception before it will be showed to user but I can't do that.
Even if I try to use a try/catch block, like so:

PHP Code:
try {
 
print_r($this->request->getPost());
}
catch (
Honeypotexception $e) {
echo 
$e->getMessage();


the print_r portion of my code is never reached.

So. How can I capture that exception to treat it before it is showed to user.


thank.
Ps. My english is a working in progress.
Reply


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