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How can if condition be used in CodeIgniter form helper?
#1

To write an if condition in CodeIgniter's form helper, you can use PHP code directly within the function call. Here's an example of how you can achieve the same view for edit and create using the form helper with an if condition:


<?= form_open_multipart("admin/leads/saved_call/{$leads_details->leads_id}/" . (!empty($call_info) ? $call_info->calls_id : ''), 'role="form" id="form" class="form-horizontal"') ?>
In the example above, the ternary operator ?: is used within the form_open_multipart() function call to check if $call_info is not empty, and if so, append its calls_id to the form action URL. If $call_info is empty, an empty string is appended instead. The rest of the attributes for the form element are passed as a string in the second argument to form_open_multipart().
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#2

This is a great example of how to use if conditions in CodeIgniter's form helper. The ternary operator ?: is a concise way to check a condition and choose one of two values based on the result. In this case, the code is checking whether $call_info is empty, and appending either its calls_id or an empty string to the form action URL accordingly.

Using PHP code directly within the function call can be a useful technique in CodeIgniter, as it allows you to build dynamic URLs and form attributes based on variables in your code. This can help reduce redundancy and make your code more maintainable.

Overall, this is a great way to achieve a consistent view for both edit and create modes in a CodeIgniter application. It's always good to keep your code clean and readable, and this technique certainly achieves that.
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#3

This was being done in CodeIgniter 2 was done in Adam Griffins Auth module and AG Auth.
What did you Try? What did you Get? What did you Expect?

Joined CodeIgniter Community 2009.  ( Skype: insitfx )
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#4

Thank you for sharing an example of how to write an if condition within CodeIgniter's form helper. The code snippet you provided demonstrates the usage of a ternary operator within the form_open_multipart() function call to conditionally append a value to the form action URL.

Here's a breakdown of the example you shared:

<?= form_open_multipart("admin/leads/saved_call/{$leads_details->leads_id}/" . (!empty($call_info) ? $call_info->calls_id : ''), 'role="form" id="form" class="form-horizontal"') ?>
The form_open_multipart() function is used to create an HTML form element with the appropriate attributes for submitting data as multipart/form-data.

The first argument is the form action URL. In your example, it includes a dynamic portion {$leads_details->leads_id}/. Additionally, the ternary operator (!empty($call_info) ? $call_info->calls_id : '') is used to conditionally append $call_info->calls_id to the URL if $call_info is not empty. Otherwise, an empty string is appended.

The second argument contains additional attributes for the form element. In this case, role="form" id="form" class="form-horizontal" is added as a string.

By utilizing this approach, you can achieve a consistent view for both editing and creating data, while dynamically modifying the form action URL based on the presence of $call_info.

Please note that this example assumes that the necessary variables ($leads_details and $call_info) are properly defined and available within the current scope.

I hope this clarifies the usage of the if condition within CodeIgniter's form helper. If you have any further questions or need additional assistance, please feel free to ask.
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