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Form Submission via Ajax.Updater
#9

[eluser]Narkboy[/eluser]
Code:
<form name="newPort" action="<?php echo site_url('/admin/insertPort');?>" method="post">

That seems to be the problem...

The onsubmit requires the url for the ajax call and the name of the form. The ajaxSubmit function then uses the passed form name to grab the elements and create a string to pass into the Ajax.Updater.

But - however I code it, the form name always returns as undefined.

So:
Code:
function ajaxSubmit(url,formIdent)
{
    document.formIdent.elements[i].value // Returns as undefined.
    document.forms[formIdent].elements[i].value // Returns as undefined.
    
    document.forms[0].elements[i].value // Returns the value.
}

I've tried other permutations as well but nothing seems to actually pass the form name through correctly.

/B


Messages In This Thread
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 04:35 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 06:55 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 06:59 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 07:26 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 07:30 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 07:35 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 08:10 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 08:59 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 10:18 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 10:30 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 10:55 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 11:32 AM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 02:14 PM
Form Submission via Ajax.Updater - by El Forum - 03-12-2009, 03:39 PM



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