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how to parse validation_errors();
#3

[eluser]srenon[/eluser]
You need to remove the newline characters before you assign it in JavaScript

$error = "passwrord filed is required......"; (on one line)

Code:
error = "<?php echo preg_replace("/(\n)+/m", ' ', strip_tags(validation_errors())));?>";

Quick Example
Code:
<?php
$error =  "passwrord filed is required.
              verfication code is required.
              first name is required.";
                        
              
        $error = preg_replace("/(\n)+/m", ' ', $error);
?>


[script language="javascript"]          
    document .write('<?= $error?>');
[/script]


Messages In This Thread
how to parse validation_errors(); - by El Forum - 07-02-2009, 07:24 AM
how to parse validation_errors(); - by El Forum - 07-02-2009, 07:38 AM
how to parse validation_errors(); - by El Forum - 07-02-2009, 05:48 PM
how to parse validation_errors(); - by El Forum - 07-02-2009, 05:59 PM
how to parse validation_errors(); - by El Forum - 07-02-2009, 06:15 PM



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