Invalid argument supplied for foreach()

[eluser]SaSa[/eluser]
[quote author="DirkZz" date="1311881674"][quote author="SaSa" date="1311881291"][quote author="NeoArc" date="1311878565"]Try this (var_export() it first ):

$config['upload_path'] = FCPATH.'uploads'.DIRECTORY_SEPARATOR;[/quote]

Where do I use this(var_export() it first )?
replaced this: $config['upload_path'] = FCPATH.'uploads'.DIRECTORY_SEPARATOR;
with: $config['upload_path'] = './uploads/';


still there is same problem...[/quote]

Maybe spend your time by reading the basics of php instead of constantly changing your nickname and asking for basic stuff.

I really want to help people, but this is getting annoying.[/quote]

what!!!!!!!!!!!!!!!!!!!!!!!!!!!!?
Please help me instead of teaching the ethics issue to be resolved.
I did not insult anyone,i respect you.
Please give comments to solve the problem?