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Menampilkan BUTTON dengan fungsi IF
#4

(This post was last modified: 05-04-2015, 07:24 AM by suhindra.)

Code:
<php if ($d->stok == ""){ ?>
<button class="btn btn-info" title="MASTER BUKU"><i class="icon-list icon-white"> </i> Master</button>
<php }else if ($d->stok == "0"){ ?>
<button class="btn btn-danger" title="BUKU TIDAK ADA"><i class="icon-remove icon-white"> </i> Pinjam</button>
<php}else{ ?>
<button class="btn btn-success"  title="BUKU ADA" onclick="return isikan_kode(\''.$id_baris.'\', \''.$d->id.'\', \''.$d->judul.'\');"><i class="icon-check icon-white"> </i> Pinjam</button>
<php }?>



Kalau gini jalan gak gan?
Reply


Messages In This Thread
Menampilkan BUTTON dengan fungsi IF - by altim20 - 05-04-2015, 03:28 AM
RE: Menampilkan BUTTON dengan fungsi IF - by suhindra - 05-04-2015, 07:21 AM



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