Class not found Error, problem with namespaces

I'm new to Codeigniter 4 and am struggling with namespaces. I tried to create a helper php2jquery.php in App/Helpers I cannot load it the way I try it. This is wat I have now.

PHP Code:

<?php namespace App\Controllers;
use App\Helpers\php2jquery;
class Test extends BaseController
{

    public function index()
    {
        
        $param = “”; //Doesn’t matter here ;
        
        $jqueryparam = New php2jquery();
    
        $data[‘jqueryobject’] = $jqueryparam->php_array_to_jquery_param($param, 4, "new FWDRAP", "FWDRAPUtils.onReady(function(){" );
        
        $data['base'] = config('App')->baseURL;
        return view('test_message',$data);
    }

    //--------------------------------------------------------------------

}

————
File: App/Helpers/php2jquery.php  (Also tried App/Helpers/php2jquery_helper.php
__________
<?php
    class php2jquery
    {
        
        function php_array_to_jquery_param($param,$indent=0, $object="", $wrapfunction=""){
            Return (“this is a test”);
        }
} 


Now, when I run it I get "Error: Class App\Helpers\php2jquery not found" I tried adding _helper tot the name and call it with and without it, but no luck. Can somebody tell me what is wrong? Thank you

Because you are doing the helper wrong see below how to do it the helper is loaded in the BaseController.

PHP Code:

<?php namespace App\Controllers;

class Test extends BaseController
{

    public function index()
    {
        
        $param = ""; //Doesn’t matter here ;
        
        $data['jqueryobject'] = phpArrayToJqueryPparam($param, 4, "new FWDRAP", "FWDRAPUtils.onReady(function(){" );
        
        $data['base'] = config('App')->baseURL;
        
        return view('test_message', $data);
    }

    //--------------------------------------------------------------------

}

————
File: app/Helpers/php2jquery_helper.php  (Also tried App/Helpers/php2jquery_helper.php
__________
<?php

if ( ! function_exists('phpArrayToJqueryParam'))
{
    function phpArrayToJqueryParam($param, $indent = 0, $object = "", $wrapfunction = "")
    {
        $tmp = 'this is a test';
        return $tmp;
    }
}

// End of app/Helpers/php2jquery_helper.php

// ------------------------------------------------------------------------

// Start app/Controllers/BaseContoller.php

<?php

namespace App\Controllers;

use CodeIgniter\Controller;
use CodeIgniter\HTTP\RequestInterface;
use CodeIgniter\HTTP\ResponseInterface;
use CodeIgniter\Services;
use Psr\Log\LoggerInterface;

/**
 * Class BaseController
 *
 * BaseController provides a convenient place for loading components
 * and performing functions that are needed by all your controllers.
 * Extend this class in any new controllers:
 *     class Home extends BaseController
 *
 * For security be sure to declare any new methods as protected or private.
 */

/**
 * Class BaseController
 *
 * @package App\Controllers
 */
class BaseController extends Controller
{
    /**
     * An array of helpers to be loaded automatically upon
     * class instantiation. These helpers will be available
     * to all other controllers that extend BaseController.
     *
     * @var array
     */
    protected $helpers = [
        'php2jquery',
    ];

    /**
     * @var \CodeIgniter\Session\Session
     */
    protected $session;

    /**
     * initController ()
     * -------------------------------------------------------------------
     *
     * @param RequestInterface  $request
     * @param ResponseInterface $response
     * @param LoggerInterface   $logger
     */
    public function initController(RequestInterface $request, ResponseInterface $response, LoggerInterface $logger)
    {
        // Do Not Edit This Line
        parent::initController($request, $response, $logger);

        //--------------------------------------------------------------------
        // Preload any models, libraries, etc, here.
        //--------------------------------------------------------------------
        // E.g.:
        // $this->session = \Config\Services::session();

        // Ensure that the session is started and running
        if (session_status() == PHP_SESSION_NONE)
        {
            $this->session = Services::session();
        }

    }

}   // -------------------------------------------------------------------

/**
 * -----------------------------------------------------------------------
 * Filename: BaseController.php
 * Location: ./app/Controllers/BaseController.php
 * -----------------------------------------------------------------------
 */ 


What did you Try? What did you Get? What did you Expect?

Joined CodeIgniter Community 2009.  ( Skype: insitfx )

Thank you for your reply, but that doesn't solve my problem. For the sake of the example I didn't post the complete helper but it's constructed as a class, not as a bunch of functions. Now if I implement it by including 'php2jquery' in the $helpers I can't call it. like this:

PHP Code:

$data['jqueryparam'] = $royalaudioparam->php_array_to_jquery_param($param,3,"new FWDRAP","FWDRAPUtils.onReady(function(){"); 


it gives me an Error: "Class 'App/Controllers/php2jquery' not found" So it seeks in the wrong namespace? (I can resolve the namespace by not using it as a helper, but it should be possible as a helper or am I missing something?
this works:

PHP Code:

<?php //BaseController
namespace App\Controllers;
use CodeIgniter\Controller;

class BaseController extends Controller
{

    protected $helpers = ['php2jquery'];
    // etc
}

?>
<?php //Controllers/Test.php
namespace App\Controllers;
use App\Helpers\php2jquery;
class Test extends BaseController
{

    public function index()
    {
        //Variables should be inited by now.
        $royalaudioparam=New php2jquery();
        $data['jqueryparam'] = $royalaudioparam->php_array_to_jquery_param($param,3,"new FWDRAP","FWDRAPUtils.onReady(function(){");
            //do something
    }
}
?>
//
<?php //Helpers/php2jquery.php
namespace App\Helpers;
class php2jquery
{
    if ( ! function_exists('phpArrayToJqueryParam')) {
        function php_array_to_jquery_param($param,$indent=0, $object="", $wrapfunction=""){
            $jquery_param="";
            $close="";
            if ($indent<3) $indent=3;
        
            $myindent=$this->indent($indent);// Inspringdiepte zetten
            // logic removed
            return rtrim($jquery_param, ",".$mynewobjectindent).PHP_EOL.$close; //Laatste comma eraf halen en afsluiten
        }
    }
    
    if ( ! function_exists('indent')) {
        function indent($pos=0) {
        
            $myindent="";
            for ($times=0; $times<=$pos; ++$times){
                //echo "pos=".$times.PHP_EOL;
            $myindent .="\t";
            }
            return $myindent;
        }
    }
    
} //class php2jquery 


but it should be possible as helper or not?

Then you should place it in Libraries or ThridParty, You need to use the use clause above the class name.

PHP Code:

// Libraries
use app\Libraries\php2jquery;

// ThirdParty
use app\ThirdParty\php2jquery; 


What did you Try? What did you Get? What did you Expect?

Joined CodeIgniter Community 2009.  ( Skype: insitfx )

With the appearance of namespaces in CI4, the location of certain libraries or helpers has become rather conditionaly.

Let's say you want to make a helper class and place it in the app/Helper directory

in file app/Helpers/Php2jquery.php

PHP Code:

<?php

namespace App\Helpers;

class Php2jquery {
    function phpArrayToJqueryParam($param, $indent = 0, $object = "", $wrapfunction = "") {
        return 'test';
    }
} 


in file app/Controllers/Test.php

PHP Code:

<?php

namespace App\Controllers;

use App\Helpers\Php2jquery;

class Test extends BaseController {

    public function index() {
        $jqueryparam = new Php2jquery();

        $data[‘jqueryobject’] = $jqueryparam->php_array_to_jquery_param($param, 4, "new FWDRAP", "FWDRAPUtils.onReady(function(){" );

        return view('index', $data);
    }
} 


Please note that the file and class name starts with a capital letter as recommended in the manual 

Thank you for your help. I’ve got it working now.