CodeIgniter 4, I have the following Controller code:
PHP Code:
$product_tier = $this->SiteModel->getProductTierByPCUID($site->id, $p->uid);
with the following model code:
PHP Code:
public function getProductTierByPCUID($site_id, $pcuid) {
$sql = 'SELECT * FROM site_product_tier WHERE site_id = ? AND pcuid = ?';
$query = $this->db->query($sql, array($site_id, $pcuid));
return $query->getRow();
}
if I echo out $product_tier immediately below the call, I get this:
PHP Code:
{
"id": "256",
"site_id": "22",
"product": "0",
"tier": "0",
"posid": "01",
"pcuid": "01",
"psprc": "0.000",
"snprc": "0.000",
"snsrc": "",
"pstat": "",
"created": "1699999047",
"updated": "1699999047",
"deleted": "0"
}
gettype($product_tier) gives me object.
However, if I run this:
PHP Code:
$used_product_tiers = array();
$product_tier = $this->SiteModel->getProductTierByPCUID($site->id, $p->uid);
if (!in_array($product_tier->id, $used_product_tiers)) {
}
I get the error:
PHP Code:
{
"title": "ErrorException",
"type": "ErrorException",
"code": 500,
"message": "Attempt to read property \"id\" on null",
"file": "/var/www/vhosts/dev.pricevision.live/httpdocs/app/Controllers/Api.php",
"line": 553,
}
Line 553 is the if statement.
What am I missing?
If I set product_tier->id to like 300 the code works, but it can;t seem to read $product_tier->id in the if statement.
